標題:
數學!!!急~~
發問:
x + 2 y = ———[x] 2 - x ans :2y - 2 x = _______ y+1 *要steps*
最佳解答:
主項變換 (change of subject) x + 2 y = ———[x] 2 - x y(2 - x) = x+2 2y - xy = x+2 2y - 2 = x + xy 2y - 2 = x(1+ y) 2y - 2 / 1+ y = x x = 2y - 2 / 1+ y ans :2y - 2 x = _______ y+1
其他解答:
y(2-x)=x+2 2y-xy=x+2 2y-2=x+xy 2y-2=x(1+y) 2y-2 ____=x 1+y 2y-2 x =____ y+1 =Ans 呵呵 自己再試下係唔係~~ 唔明add 我msn~~ sophialucky@hotmail.com|||||y = (x+2) / (2-x) y(2-x) = x+2 2y-xy=x+2 2y-2=x+xy 2y-2=x(1+y) (2y-2)/(1+y)=x Therefore, x= (2y-2) / (y+1)|||||y(2-x) = x+2 ___ (2-x) 2-x 2y-xy = x+2 2y-2 = x + xy 2y-2 = x(y+1) 2y-2 = x(y+1) ___ _____ y+1 y+1 x = 2y -2 _____ y+1 吾明可以再問我..|||||x x x x xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
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